Module 1 Part 2 Linear Inequalities
2026-02-28 19:11
Tags: #math
Author: Duke Hsu
Module 1 Part 2 - Linear Inequalities
Single Variable
inequality
- inequality: An inequality is like an equation, but instead of an equal sign (=), is has one of these signs:
| SYMBOL | MEANING |
|---|---|
| \(<\) | less than |
| \(\le\) | less than or equal to |
| \(>\) | greater than |
| \(\ge\) | greater than or equal to |
Graphing
- number line
Example:
Graphing Rules (number line):
| SYMBOL | CIRCLE | DIRECTION OF ARROW |
|---|---|---|
| \(<\) | open | left |
| \(>\) | open | right |
| \(\le\) | closed | left |
| \(\ge\) | closed | right |
Interval Notation
| SYMBOL | MEANING | READING |
|---|---|---|
| \((\quad)\) | endpoint NOT included | Parentheses |
| \([\quad]\) | endpoint included | Brackets |
| \(\infty \quad -\infty\) | always use in parentheses | infinity |
Set Builder Notation
use curly braces { }
Formart: \({x \quad| \quad condition}\)
Meaning:
The set of all \(x\) such that the conditions is true .
Example:
\(x > 3\), \(\{x | x > 3\}\)
Example
Question 1:
\(-3x +4 <13\)
Note
兩邊都減去4 , 然後再除以-3
(因為9 除以負數,所以要轉換符號)
\(x >-3\)
Step1-Number line
Step2-Interval Notation
\((-3,\infty )\)
Step3- Set Builder Notation
\(\{x\quad| \quad x > -3 \}\)
Value of \(x\): \(x=-2,-1,0,1,2,3,4,5...\)
Question 2:
\(-5 \le x \le -1\)
Step2- Interval Notation
\([-5,-1]\)
Step3- Set Builder Notation
\(\{x | -5\le x \le -1\}\)
Values of \(x\) : \(x=-5,-4,-3,-2,-1\)
Question 3:
\(x < -3 \quad or \quad x > 3\)
Step1 Number line
Step2 Interval Notation
\((- \infty , -3) \quad (3, \infty)\)
Step3 Set Builder Notation
\(\{x\quad | \quad x<-3\}\quad U \quad \{x\quad |\quad x>3\}\)
Values of \(x\):
\(x= -4,-5,-6,-7,-8,-9.....\) \(x=4,5,6,7,8,9,10\)
Question 4:
\(x\le -5 \quad or\quad x>10\)
Step1 Number line
Step2 Interval Notation
\((-\infty, -5]\) \((10,\infty)\)
Step3 Set Builder Notation
\(\{x\quad | \quad x\le-5\}\quad U \quad \{x\quad |\quad x>10\}\)
Values of \(x\):
\(x=-5,-6,-7,-8,....\)
\(x=11,12,13,14,15\)
Question 5:
\(5+x\ge7\)
\(x\ge 2\)
Step1 Number line
Step2 Interval Notation
\([2,\infty)\)
Step3 Set Builder Notation
\(\{x \quad | \quad x \ge 2\}\)
Values of x: \(x=2,3,4,5,6,7,8,9.....\)
Question 6:
\(\frac{x}{3} \ge 5\)
Multiply both side by : 3 * (x/3) >= 5 * 3
left side x, right side 15,
Result: \(x \ge 15\)
Step1: Number line
Step2: Interval Notation
\([15, \infty)\)
Step3: Set Builder Notation
\(\{x\quad |\quad x \ge15\}\)
Values of x: \(x= 15,16,17,18,19,20,21,.....\)
Question 7:
\(-2\le x+1 \le 4\)
Calculator \(x\):
\(\because\) \((-2)-(-1) \le x \le 4-1\)
\(\therefore\) \(-3\le x \le 3\)
Step1 Number line
Step2 Interval Notation
\([-3,3]\)
Step3 Set Builder Notation
\(\{x| -2\le x+1 \le4\}\)
Values of \(x\):
\(x=-3,-2,-1,0,1,2,3\)
Solving it in Two variable
Quadrant Graph
Two types of Line
| LINE NAME | EXAMPLE | SYMBOL |
|---|---|---|
| Dotted line | -------- | \(>,<\) |
| Solid line | ——— | \(\ge,\le\) |
Example:
Note
垂直線(Vertical Line): inequality 中只有x , 沒有y;
Note
水平線 (Horizontal Line): inequality 中只有y, 沒有x;
Note
斜線 (Slanted/Oblique Line) inequality 中有y,也有x;
Graph the inequality
Question : \(3x-5y\ge 15\)
Step 1. Replace inequality symbol with equals sign: \(3x – 5y = 15\)
Step 2. Graph the line
Calculator the point:
| x | y |
|---|---|
| 0 | -3 |
| 5 | 0 |
point A: (0,-3) point B: (5,0)
Since: \(\ge\) , therefor is Solid Line, and in QIV,
如何判斷二元一次不等式的區域(Range) (如何畫出陰影)
當你畫出一條直線(例如 \(2x + 4y = 8\))後,這條線把坐標平面分成了兩半。要判斷該塗哪一邊,最簡單的方法是「原點測試法」。
-
式子: \(2x + 4y \leq 8\)
-
步驟:
-
先畫出直線 \(2x + 4y = 8\)(通過 \((4, 0)\) 和 \((0, 2)\))。
-
找一個不在線上的點代入。最方便的就是原點 \((0, 0)\)。
-
將 \(x=0, y=0\) 代入不等式:
\[2(0) + 4(0) \leq 8 \implies 0 \leq 8\] -
判斷: \(0 \leq 8\) 是成立的。這代表原點所在的區域就是「正確的區域」。
-
結論: 塗向包含 \((0, 0)\) 的那一側(即直線的左下方)。
-
References
Module 1 PDF
Gemini tools - https://gemini.google.com/share/b3c0ec6c89db











